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This part of the challenge series introduces polyhomophonic substitution. In a polyhomophonic substitution cipher, each ciphertext symbol can represent one of several plaintext symbols, and each plaintext letter can be encrypted as one of several ciphertext letters. The key is a mapping from the set of plaintext symbols to the set of ciphertext symbols. Read more...
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Author:
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Published on: 2020-04-06 20:44 |
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Maximum number of attempts for this challenge: 15 |
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All successful users of this challenge
| Rank |
User (#14) |
Achieved points (Global score) |
y-m-d - h:m:s |
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Armin Krauss (argh)
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2000 (206965) |
2020-04-06 22:29:12 |
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Snake (snk)
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2000 (187783) |
2020-04-07 08:54:32 |
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Thomas (Thomas4897)
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2000 (36141) |
2020-04-07 14:25:54 |
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Dominik M. (Sgt. Pepper)
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2000 (128575) |
2020-04-07 14:59:45 |
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#5 |
Kurt Gebauer (Yokozuna)
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2000 (282608) |
2020-04-07 15:25:09 |
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#6 |
Viktor (Veselovský)
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2000 (169444) |
2020-04-07 15:49:37 |
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#7 |
J-L Morel (Rossignol)
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1433 (42130) |
2020-04-20 11:01:25 |
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#8 |
D3d4lu5 (D3d4lu5)
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1337 (363488) |
2020-05-06 18:16:08 |
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#9 |
George Lasry (george4096)
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1310 (399565) |
2020-05-14 23:52:33 |
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#10 |
Norbert Biermann (Norbert)
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1284 (47790) |
2020-05-27 15:29:25 |
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#11 |
Alain Collignon (vexilla72)
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1199 (123666) |
2020-09-16 08:49:49 |
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#12 |
Michael (FoM)
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1174 (57794) |
2020-12-18 02:33:31 |
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#13 |
Luigi Tomelli (archstanton)
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1154 (127538) |
2021-05-01 18:20:58 |
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#14 |
Eric (ExAstris)
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1151 (54941) |
2021-05-29 19:54:05 |
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